3.13.9 \(\int \frac {(a+b \tan (e+f x))^4}{c+d \tan (e+f x)} \, dx\) [1209]

Optimal. Leaf size=190 \[ \frac {\left (a^4 c-6 a^2 b^2 c+b^4 c+4 a^3 b d-4 a b^3 d\right ) x}{c^2+d^2}-\frac {\left (4 a^3 b c-4 a b^3 c-a^4 d+6 a^2 b^2 d-b^4 d\right ) \log (\cos (e+f x))}{\left (c^2+d^2\right ) f}+\frac {(b c-a d)^4 \log (c+d \tan (e+f x))}{d^3 \left (c^2+d^2\right ) f}-\frac {b^3 (b c-3 a d) \tan (e+f x)}{d^2 f}+\frac {b^2 (a+b \tan (e+f x))^2}{2 d f} \]

[Out]

(a^4*c+4*a^3*b*d-6*a^2*b^2*c-4*a*b^3*d+b^4*c)*x/(c^2+d^2)-(-a^4*d+4*a^3*b*c+6*a^2*b^2*d-4*a*b^3*c-b^4*d)*ln(co
s(f*x+e))/(c^2+d^2)/f+(-a*d+b*c)^4*ln(c+d*tan(f*x+e))/d^3/(c^2+d^2)/f-b^3*(-3*a*d+b*c)*tan(f*x+e)/d^2/f+1/2*b^
2*(a+b*tan(f*x+e))^2/d/f

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Rubi [A]
time = 0.33, antiderivative size = 190, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.240, Rules used = {3647, 3718, 3707, 3698, 31, 3556} \begin {gather*} -\frac {\left (a^4 (-d)+4 a^3 b c+6 a^2 b^2 d-4 a b^3 c-b^4 d\right ) \log (\cos (e+f x))}{f \left (c^2+d^2\right )}+\frac {x \left (a^4 c+4 a^3 b d-6 a^2 b^2 c-4 a b^3 d+b^4 c\right )}{c^2+d^2}-\frac {b^3 (b c-3 a d) \tan (e+f x)}{d^2 f}+\frac {b^2 (a+b \tan (e+f x))^2}{2 d f}+\frac {(b c-a d)^4 \log (c+d \tan (e+f x))}{d^3 f \left (c^2+d^2\right )} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*Tan[e + f*x])^4/(c + d*Tan[e + f*x]),x]

[Out]

((a^4*c - 6*a^2*b^2*c + b^4*c + 4*a^3*b*d - 4*a*b^3*d)*x)/(c^2 + d^2) - ((4*a^3*b*c - 4*a*b^3*c - a^4*d + 6*a^
2*b^2*d - b^4*d)*Log[Cos[e + f*x]])/((c^2 + d^2)*f) + ((b*c - a*d)^4*Log[c + d*Tan[e + f*x]])/(d^3*(c^2 + d^2)
*f) - (b^3*(b*c - 3*a*d)*Tan[e + f*x])/(d^2*f) + (b^2*(a + b*Tan[e + f*x])^2)/(2*d*f)

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 3556

Int[tan[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-Log[RemoveContent[Cos[c + d*x], x]]/d, x] /; FreeQ[{c, d}, x]

Rule 3647

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Si
mp[b^2*(a + b*Tan[e + f*x])^(m - 2)*((c + d*Tan[e + f*x])^(n + 1)/(d*f*(m + n - 1))), x] + Dist[1/(d*(m + n -
1)), Int[(a + b*Tan[e + f*x])^(m - 3)*(c + d*Tan[e + f*x])^n*Simp[a^3*d*(m + n - 1) - b^2*(b*c*(m - 2) + a*d*(
1 + n)) + b*d*(m + n - 1)*(3*a^2 - b^2)*Tan[e + f*x] - b^2*(b*c*(m - 2) - a*d*(3*m + 2*n - 4))*Tan[e + f*x]^2,
x], x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0]
&& IntegerQ[2*m] && GtQ[m, 2] && (GeQ[n, -1] || IntegerQ[m]) &&  !(IGtQ[n, 2] && ( !IntegerQ[m] || (EqQ[c, 0]
&& NeQ[a, 0])))

Rule 3698

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_.)*((A_) + (C_.)*tan[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Dist[
A/(b*f), Subst[Int[(a + x)^m, x], x, b*Tan[e + f*x]], x] /; FreeQ[{a, b, e, f, A, C, m}, x] && EqQ[A, C]

Rule 3707

Int[((A_) + (B_.)*tan[(e_.) + (f_.)*(x_)] + (C_.)*tan[(e_.) + (f_.)*(x_)]^2)/((a_.) + (b_.)*tan[(e_.) + (f_.)*
(x_)]), x_Symbol] :> Simp[(a*A + b*B - a*C)*(x/(a^2 + b^2)), x] + (Dist[(A*b^2 - a*b*B + a^2*C)/(a^2 + b^2), I
nt[(1 + Tan[e + f*x]^2)/(a + b*Tan[e + f*x]), x], x] - Dist[(A*b - a*B - b*C)/(a^2 + b^2), Int[Tan[e + f*x], x
], x]) /; FreeQ[{a, b, e, f, A, B, C}, x] && NeQ[A*b^2 - a*b*B + a^2*C, 0] && NeQ[a^2 + b^2, 0] && NeQ[A*b - a
*B - b*C, 0]

Rule 3718

Int[((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_.)*((A_.) + (B_.)*tan[(e
_.) + (f_.)*(x_)] + (C_.)*tan[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[b*C*Tan[e + f*x]*((c + d*Tan[e + f*x])
^(n + 1)/(d*f*(n + 2))), x] - Dist[1/(d*(n + 2)), Int[(c + d*Tan[e + f*x])^n*Simp[b*c*C - a*A*d*(n + 2) - (A*b
+ a*B - b*C)*d*(n + 2)*Tan[e + f*x] - (a*C*d*(n + 2) - b*(c*C - B*d*(n + 2)))*Tan[e + f*x]^2, x], x], x] /; F
reeQ[{a, b, c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[c^2 + d^2, 0] &&  !LtQ[n, -1]

Rubi steps

\begin {align*} \int \frac {(a+b \tan (e+f x))^4}{c+d \tan (e+f x)} \, dx &=\frac {b^2 (a+b \tan (e+f x))^2}{2 d f}+\frac {\int \frac {(a+b \tan (e+f x)) \left (-2 \left (b^3 c-a^3 d\right )+2 b \left (3 a^2-b^2\right ) d \tan (e+f x)-2 b^2 (b c-3 a d) \tan ^2(e+f x)\right )}{c+d \tan (e+f x)} \, dx}{2 d}\\ &=-\frac {b^3 (b c-3 a d) \tan (e+f x)}{d^2 f}+\frac {b^2 (a+b \tan (e+f x))^2}{2 d f}-\frac {\int \frac {-2 \left (b^4 c^2-4 a b^3 c d+a^4 d^2\right )-8 a b \left (a^2-b^2\right ) d^2 \tan (e+f x)+2 b^2 \left (4 a b c d-6 a^2 d^2-b^2 \left (c^2-d^2\right )\right ) \tan ^2(e+f x)}{c+d \tan (e+f x)} \, dx}{2 d^2}\\ &=\frac {\left (a^4 c-6 a^2 b^2 c+b^4 c+4 a^3 b d-4 a b^3 d\right ) x}{c^2+d^2}-\frac {b^3 (b c-3 a d) \tan (e+f x)}{d^2 f}+\frac {b^2 (a+b \tan (e+f x))^2}{2 d f}+\frac {(b c-a d)^4 \int \frac {1+\tan ^2(e+f x)}{c+d \tan (e+f x)} \, dx}{d^2 \left (c^2+d^2\right )}+\frac {\left (4 a^3 b c-4 a b^3 c-a^4 d+6 a^2 b^2 d-b^4 d\right ) \int \tan (e+f x) \, dx}{c^2+d^2}\\ &=\frac {\left (a^4 c-6 a^2 b^2 c+b^4 c+4 a^3 b d-4 a b^3 d\right ) x}{c^2+d^2}-\frac {\left (4 a^3 b c-4 a b^3 c-a^4 d+6 a^2 b^2 d-b^4 d\right ) \log (\cos (e+f x))}{\left (c^2+d^2\right ) f}-\frac {b^3 (b c-3 a d) \tan (e+f x)}{d^2 f}+\frac {b^2 (a+b \tan (e+f x))^2}{2 d f}+\frac {(b c-a d)^4 \text {Subst}\left (\int \frac {1}{c+x} \, dx,x,d \tan (e+f x)\right )}{d^3 \left (c^2+d^2\right ) f}\\ &=\frac {\left (a^4 c-6 a^2 b^2 c+b^4 c+4 a^3 b d-4 a b^3 d\right ) x}{c^2+d^2}-\frac {\left (4 a^3 b c-4 a b^3 c-a^4 d+6 a^2 b^2 d-b^4 d\right ) \log (\cos (e+f x))}{\left (c^2+d^2\right ) f}+\frac {(b c-a d)^4 \log (c+d \tan (e+f x))}{d^3 \left (c^2+d^2\right ) f}-\frac {b^3 (b c-3 a d) \tan (e+f x)}{d^2 f}+\frac {b^2 (a+b \tan (e+f x))^2}{2 d f}\\ \end {align*}

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Mathematica [C] Result contains complex when optimal does not.
time = 1.30, size = 160, normalized size = 0.84 \begin {gather*} \frac {\frac {\frac {(a+i b)^4 d^2 \log (i-\tan (e+f x))}{i c-d}-\frac {(a-i b)^4 d^2 \log (i+\tan (e+f x))}{i c+d}+\frac {2 (b c-a d)^4 \log (c+d \tan (e+f x))}{d \left (c^2+d^2\right )}}{d}-\frac {2 b^3 (b c-3 a d) \tan (e+f x)}{d}+b^2 (a+b \tan (e+f x))^2}{2 d f} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*Tan[e + f*x])^4/(c + d*Tan[e + f*x]),x]

[Out]

((((a + I*b)^4*d^2*Log[I - Tan[e + f*x]])/(I*c - d) - ((a - I*b)^4*d^2*Log[I + Tan[e + f*x]])/(I*c + d) + (2*(
b*c - a*d)^4*Log[c + d*Tan[e + f*x]])/(d*(c^2 + d^2)))/d - (2*b^3*(b*c - 3*a*d)*Tan[e + f*x])/d + b^2*(a + b*T
an[e + f*x])^2)/(2*d*f)

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Maple [A]
time = 0.23, size = 221, normalized size = 1.16

method	result	size
derivativedivides	\(\frac {\frac {b^{3} \left (\frac {b d \left (\tan ^{2}\left (f x +e \right )\right )}{2}+4 a d \tan \left (f x +e \right )-b c \tan \left (f x +e \right )\right )}{d^{2}}+\frac {\frac {\left (-a^{4} d +4 a^{3} b c +6 a^{2} b^{2} d -4 a \,b^{3} c -b^{4} d \right ) \ln \left (1+\tan ^{2}\left (f x +e \right )\right )}{2}+\left (a^{4} c +4 a^{3} b d -6 a^{2} b^{2} c -4 b^{3} d a +b^{4} c \right ) \arctan \left (\tan \left (f x +e \right )\right )}{c^{2}+d^{2}}+\frac {\left (a^{4} d^{4}-4 a^{3} b c \,d^{3}+6 a^{2} b^{2} c^{2} d^{2}-4 a \,b^{3} c^{3} d +b^{4} c^{4}\right ) \ln \left (c +d \tan \left (f x +e \right )\right )}{d^{3} \left (c^{2}+d^{2}\right )}}{f}\)	\(221\)
default	\(\frac {\frac {b^{3} \left (\frac {b d \left (\tan ^{2}\left (f x +e \right )\right )}{2}+4 a d \tan \left (f x +e \right )-b c \tan \left (f x +e \right )\right )}{d^{2}}+\frac {\frac {\left (-a^{4} d +4 a^{3} b c +6 a^{2} b^{2} d -4 a \,b^{3} c -b^{4} d \right ) \ln \left (1+\tan ^{2}\left (f x +e \right )\right )}{2}+\left (a^{4} c +4 a^{3} b d -6 a^{2} b^{2} c -4 b^{3} d a +b^{4} c \right ) \arctan \left (\tan \left (f x +e \right )\right )}{c^{2}+d^{2}}+\frac {\left (a^{4} d^{4}-4 a^{3} b c \,d^{3}+6 a^{2} b^{2} c^{2} d^{2}-4 a \,b^{3} c^{3} d +b^{4} c^{4}\right ) \ln \left (c +d \tan \left (f x +e \right )\right )}{d^{3} \left (c^{2}+d^{2}\right )}}{f}\)	\(221\)
norman	\(\frac {\left (a^{4} c +4 a^{3} b d -6 a^{2} b^{2} c -4 b^{3} d a +b^{4} c \right ) x}{c^{2}+d^{2}}+\frac {b^{3} \left (4 a d -b c \right ) \tan \left (f x +e \right )}{d^{2} f}+\frac {b^{4} \left (\tan ^{2}\left (f x +e \right )\right )}{2 d f}+\frac {\left (a^{4} d^{4}-4 a^{3} b c \,d^{3}+6 a^{2} b^{2} c^{2} d^{2}-4 a \,b^{3} c^{3} d +b^{4} c^{4}\right ) \ln \left (c +d \tan \left (f x +e \right )\right )}{\left (c^{2}+d^{2}\right ) d^{3} f}-\frac {\left (a^{4} d -4 a^{3} b c -6 a^{2} b^{2} d +4 a \,b^{3} c +b^{4} d \right ) \ln \left (1+\tan ^{2}\left (f x +e \right )\right )}{2 f \left (c^{2}+d^{2}\right )}\)	\(226\)
risch	\(-\frac {12 i a^{2} b^{2} c^{2} e}{\left (c^{2}+d^{2}\right ) d f}+\frac {8 i a \,b^{3} c^{3} e}{\left (c^{2}+d^{2}\right ) d^{2} f}-\frac {4 i x \,b^{3} a}{i d -c}+\frac {12 i b^{2} a^{2} x}{d}+\frac {2 i b^{4} c^{2} x}{d^{3}}-\frac {2 i b^{4} e}{d f}-\frac {2 i d \,a^{4} x}{c^{2}+d^{2}}+\frac {d \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {i d +c}{i d -c}\right ) a^{4}}{\left (c^{2}+d^{2}\right ) f}+\frac {4 i x \,a^{3} b}{i d -c}-\frac {6 b^{2} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right ) a^{2}}{d f}-\frac {b^{4} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right ) c^{2}}{d^{3} f}+\frac {6 x \,a^{2} b^{2}}{i d -c}-\frac {2 i b^{4} x}{d}+\frac {b^{4} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )}{d f}+\frac {4 b^{3} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right ) a c}{d^{2} f}-\frac {4 \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {i d +c}{i d -c}\right ) a^{3} b c}{\left (c^{2}+d^{2}\right ) f}+\frac {\ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {i d +c}{i d -c}\right ) b^{4} c^{4}}{\left (c^{2}+d^{2}\right ) d^{3} f}+\frac {2 i b^{3} \left (4 a d \,{\mathrm e}^{2 i \left (f x +e \right )}-b c \,{\mathrm e}^{2 i \left (f x +e \right )}-i b d \,{\mathrm e}^{2 i \left (f x +e \right )}+4 a d -b c \right )}{d^{2} f \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )^{2}}+\frac {12 i b^{2} a^{2} e}{d f}-\frac {8 i b^{3} a c x}{d^{2}}+\frac {2 i b^{4} c^{2} e}{d^{3} f}-\frac {2 i d \,a^{4} e}{\left (c^{2}+d^{2}\right ) f}+\frac {8 i a^{3} b c x}{c^{2}+d^{2}}-\frac {2 i b^{4} c^{4} x}{\left (c^{2}+d^{2}\right ) d^{3}}-\frac {8 i b^{3} a c e}{d^{2} f}+\frac {8 i a^{3} b c e}{\left (c^{2}+d^{2}\right ) f}-\frac {12 i a^{2} b^{2} c^{2} x}{\left (c^{2}+d^{2}\right ) d}+\frac {8 i a \,b^{3} c^{3} x}{\left (c^{2}+d^{2}\right ) d^{2}}-\frac {2 i b^{4} c^{4} e}{\left (c^{2}+d^{2}\right ) d^{3} f}+\frac {6 \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {i d +c}{i d -c}\right ) a^{2} b^{2} c^{2}}{\left (c^{2}+d^{2}\right ) d f}-\frac {4 \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {i d +c}{i d -c}\right ) a \,b^{3} c^{3}}{\left (c^{2}+d^{2}\right ) d^{2} f}-\frac {x \,b^{4}}{i d -c}-\frac {x \,a^{4}}{i d -c}\)	\(848\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*tan(f*x+e))^4/(c+d*tan(f*x+e)),x,method=_RETURNVERBOSE)

[Out]

1/f*(b^3/d^2*(1/2*b*d*tan(f*x+e)^2+4*a*d*tan(f*x+e)-b*c*tan(f*x+e))+1/(c^2+d^2)*(1/2*(-a^4*d+4*a^3*b*c+6*a^2*b
^2*d-4*a*b^3*c-b^4*d)*ln(1+tan(f*x+e)^2)+(a^4*c+4*a^3*b*d-6*a^2*b^2*c-4*a*b^3*d+b^4*c)*arctan(tan(f*x+e)))+1/d
^3*(a^4*d^4-4*a^3*b*c*d^3+6*a^2*b^2*c^2*d^2-4*a*b^3*c^3*d+b^4*c^4)/(c^2+d^2)*ln(c+d*tan(f*x+e)))

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Maxima [A]
time = 0.64, size = 229, normalized size = 1.21 \begin {gather*} \frac {\frac {2 \, {\left ({\left (a^{4} - 6 \, a^{2} b^{2} + b^{4}\right )} c + 4 \, {\left (a^{3} b - a b^{3}\right )} d\right )} {\left (f x + e\right )}}{c^{2} + d^{2}} + \frac {2 \, {\left (b^{4} c^{4} - 4 \, a b^{3} c^{3} d + 6 \, a^{2} b^{2} c^{2} d^{2} - 4 \, a^{3} b c d^{3} + a^{4} d^{4}\right )} \log \left (d \tan \left (f x + e\right ) + c\right )}{c^{2} d^{3} + d^{5}} + \frac {{\left (4 \, {\left (a^{3} b - a b^{3}\right )} c - {\left (a^{4} - 6 \, a^{2} b^{2} + b^{4}\right )} d\right )} \log \left (\tan \left (f x + e\right )^{2} + 1\right )}{c^{2} + d^{2}} + \frac {b^{4} d \tan \left (f x + e\right )^{2} - 2 \, {\left (b^{4} c - 4 \, a b^{3} d\right )} \tan \left (f x + e\right )}{d^{2}}}{2 \, f} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*tan(f*x+e))^4/(c+d*tan(f*x+e)),x, algorithm="maxima")

[Out]

1/2*(2*((a^4 - 6*a^2*b^2 + b^4)*c + 4*(a^3*b - a*b^3)*d)*(f*x + e)/(c^2 + d^2) + 2*(b^4*c^4 - 4*a*b^3*c^3*d +
6*a^2*b^2*c^2*d^2 - 4*a^3*b*c*d^3 + a^4*d^4)*log(d*tan(f*x + e) + c)/(c^2*d^3 + d^5) + (4*(a^3*b - a*b^3)*c -
(a^4 - 6*a^2*b^2 + b^4)*d)*log(tan(f*x + e)^2 + 1)/(c^2 + d^2) + (b^4*d*tan(f*x + e)^2 - 2*(b^4*c - 4*a*b^3*d)
*tan(f*x + e))/d^2)/f

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Fricas [A]
time = 1.61, size = 305, normalized size = 1.61 \begin {gather*} \frac {2 \, {\left ({\left (a^{4} - 6 \, a^{2} b^{2} + b^{4}\right )} c d^{3} + 4 \, {\left (a^{3} b - a b^{3}\right )} d^{4}\right )} f x + {\left (b^{4} c^{2} d^{2} + b^{4} d^{4}\right )} \tan \left (f x + e\right )^{2} + {\left (b^{4} c^{4} - 4 \, a b^{3} c^{3} d + 6 \, a^{2} b^{2} c^{2} d^{2} - 4 \, a^{3} b c d^{3} + a^{4} d^{4}\right )} \log \left (\frac {d^{2} \tan \left (f x + e\right )^{2} + 2 \, c d \tan \left (f x + e\right ) + c^{2}}{\tan \left (f x + e\right )^{2} + 1}\right ) - {\left (b^{4} c^{4} - 4 \, a b^{3} c^{3} d + 6 \, a^{2} b^{2} c^{2} d^{2} - 4 \, a b^{3} c d^{3} + {\left (6 \, a^{2} b^{2} - b^{4}\right )} d^{4}\right )} \log \left (\frac {1}{\tan \left (f x + e\right )^{2} + 1}\right ) - 2 \, {\left (b^{4} c^{3} d - 4 \, a b^{3} c^{2} d^{2} + b^{4} c d^{3} - 4 \, a b^{3} d^{4}\right )} \tan \left (f x + e\right )}{2 \, {\left (c^{2} d^{3} + d^{5}\right )} f} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*tan(f*x+e))^4/(c+d*tan(f*x+e)),x, algorithm="fricas")

[Out]

1/2*(2*((a^4 - 6*a^2*b^2 + b^4)*c*d^3 + 4*(a^3*b - a*b^3)*d^4)*f*x + (b^4*c^2*d^2 + b^4*d^4)*tan(f*x + e)^2 +
(b^4*c^4 - 4*a*b^3*c^3*d + 6*a^2*b^2*c^2*d^2 - 4*a^3*b*c*d^3 + a^4*d^4)*log((d^2*tan(f*x + e)^2 + 2*c*d*tan(f*
x + e) + c^2)/(tan(f*x + e)^2 + 1)) - (b^4*c^4 - 4*a*b^3*c^3*d + 6*a^2*b^2*c^2*d^2 - 4*a*b^3*c*d^3 + (6*a^2*b^
2 - b^4)*d^4)*log(1/(tan(f*x + e)^2 + 1)) - 2*(b^4*c^3*d - 4*a*b^3*c^2*d^2 + b^4*c*d^3 - 4*a*b^3*d^4)*tan(f*x
+ e))/((c^2*d^3 + d^5)*f)

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Sympy [C] Result contains complex when optimal does not.
time = 1.37, size = 2516, normalized size = 13.24 \begin {gather*} \text {Too large to display} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*tan(f*x+e))**4/(c+d*tan(f*x+e)),x)

[Out]

Piecewise((zoo*x*(a + b*tan(e))**4/tan(e), Eq(c, 0) & Eq(d, 0) & Eq(f, 0)), (I*a**4*f*x*tan(e + f*x)/(2*d*f*ta
n(e + f*x) - 2*I*d*f) + a**4*f*x/(2*d*f*tan(e + f*x) - 2*I*d*f) + I*a**4/(2*d*f*tan(e + f*x) - 2*I*d*f) + 4*a*
*3*b*f*x*tan(e + f*x)/(2*d*f*tan(e + f*x) - 2*I*d*f) - 4*I*a**3*b*f*x/(2*d*f*tan(e + f*x) - 2*I*d*f) - 4*a**3*
b/(2*d*f*tan(e + f*x) - 2*I*d*f) + 6*I*a**2*b**2*f*x*tan(e + f*x)/(2*d*f*tan(e + f*x) - 2*I*d*f) + 6*a**2*b**2
*f*x/(2*d*f*tan(e + f*x) - 2*I*d*f) + 6*a**2*b**2*log(tan(e + f*x)**2 + 1)*tan(e + f*x)/(2*d*f*tan(e + f*x) -
2*I*d*f) - 6*I*a**2*b**2*log(tan(e + f*x)**2 + 1)/(2*d*f*tan(e + f*x) - 2*I*d*f) - 6*I*a**2*b**2/(2*d*f*tan(e
+ f*x) - 2*I*d*f) - 12*a*b**3*f*x*tan(e + f*x)/(2*d*f*tan(e + f*x) - 2*I*d*f) + 12*I*a*b**3*f*x/(2*d*f*tan(e +
f*x) - 2*I*d*f) + 4*I*a*b**3*log(tan(e + f*x)**2 + 1)*tan(e + f*x)/(2*d*f*tan(e + f*x) - 2*I*d*f) + 4*a*b**3*
log(tan(e + f*x)**2 + 1)/(2*d*f*tan(e + f*x) - 2*I*d*f) + 8*a*b**3*tan(e + f*x)**2/(2*d*f*tan(e + f*x) - 2*I*d
*f) + 12*a*b**3/(2*d*f*tan(e + f*x) - 2*I*d*f) - 3*I*b**4*f*x*tan(e + f*x)/(2*d*f*tan(e + f*x) - 2*I*d*f) - 3*
b**4*f*x/(2*d*f*tan(e + f*x) - 2*I*d*f) - 2*b**4*log(tan(e + f*x)**2 + 1)*tan(e + f*x)/(2*d*f*tan(e + f*x) - 2
*I*d*f) + 2*I*b**4*log(tan(e + f*x)**2 + 1)/(2*d*f*tan(e + f*x) - 2*I*d*f) + b**4*tan(e + f*x)**3/(2*d*f*tan(e
+ f*x) - 2*I*d*f) + I*b**4*tan(e + f*x)**2/(2*d*f*tan(e + f*x) - 2*I*d*f) + 3*I*b**4/(2*d*f*tan(e + f*x) - 2*
I*d*f), Eq(c, -I*d)), (-I*a**4*f*x*tan(e + f*x)/(2*d*f*tan(e + f*x) + 2*I*d*f) + a**4*f*x/(2*d*f*tan(e + f*x)
+ 2*I*d*f) - I*a**4/(2*d*f*tan(e + f*x) + 2*I*d*f) + 4*a**3*b*f*x*tan(e + f*x)/(2*d*f*tan(e + f*x) + 2*I*d*f)
+ 4*I*a**3*b*f*x/(2*d*f*tan(e + f*x) + 2*I*d*f) - 4*a**3*b/(2*d*f*tan(e + f*x) + 2*I*d*f) - 6*I*a**2*b**2*f*x*
tan(e + f*x)/(2*d*f*tan(e + f*x) + 2*I*d*f) + 6*a**2*b**2*f*x/(2*d*f*tan(e + f*x) + 2*I*d*f) + 6*a**2*b**2*log
(tan(e + f*x)**2 + 1)*tan(e + f*x)/(2*d*f*tan(e + f*x) + 2*I*d*f) + 6*I*a**2*b**2*log(tan(e + f*x)**2 + 1)/(2*
d*f*tan(e + f*x) + 2*I*d*f) + 6*I*a**2*b**2/(2*d*f*tan(e + f*x) + 2*I*d*f) - 12*a*b**3*f*x*tan(e + f*x)/(2*d*f
*tan(e + f*x) + 2*I*d*f) - 12*I*a*b**3*f*x/(2*d*f*tan(e + f*x) + 2*I*d*f) - 4*I*a*b**3*log(tan(e + f*x)**2 + 1
)*tan(e + f*x)/(2*d*f*tan(e + f*x) + 2*I*d*f) + 4*a*b**3*log(tan(e + f*x)**2 + 1)/(2*d*f*tan(e + f*x) + 2*I*d*
f) + 8*a*b**3*tan(e + f*x)**2/(2*d*f*tan(e + f*x) + 2*I*d*f) + 12*a*b**3/(2*d*f*tan(e + f*x) + 2*I*d*f) + 3*I*
b**4*f*x*tan(e + f*x)/(2*d*f*tan(e + f*x) + 2*I*d*f) - 3*b**4*f*x/(2*d*f*tan(e + f*x) + 2*I*d*f) - 2*b**4*log(
tan(e + f*x)**2 + 1)*tan(e + f*x)/(2*d*f*tan(e + f*x) + 2*I*d*f) - 2*I*b**4*log(tan(e + f*x)**2 + 1)/(2*d*f*ta
n(e + f*x) + 2*I*d*f) + b**4*tan(e + f*x)**3/(2*d*f*tan(e + f*x) + 2*I*d*f) - I*b**4*tan(e + f*x)**2/(2*d*f*ta
n(e + f*x) + 2*I*d*f) - 3*I*b**4/(2*d*f*tan(e + f*x) + 2*I*d*f), Eq(c, I*d)), ((a**4*x + 2*a**3*b*log(tan(e +
f*x)**2 + 1)/f - 6*a**2*b**2*x + 6*a**2*b**2*tan(e + f*x)/f - 2*a*b**3*log(tan(e + f*x)**2 + 1)/f + 2*a*b**3*t
an(e + f*x)**2/f + b**4*x + b**4*tan(e + f*x)**3/(3*f) - b**4*tan(e + f*x)/f)/c, Eq(d, 0)), (x*(a + b*tan(e))*
*4/(c + d*tan(e)), Eq(f, 0)), (2*a**4*c*d**3*f*x/(2*c**2*d**3*f + 2*d**5*f) + 2*a**4*d**4*log(c/d + tan(e + f*
x))/(2*c**2*d**3*f + 2*d**5*f) - a**4*d**4*log(tan(e + f*x)**2 + 1)/(2*c**2*d**3*f + 2*d**5*f) - 8*a**3*b*c*d*
*3*log(c/d + tan(e + f*x))/(2*c**2*d**3*f + 2*d**5*f) + 4*a**3*b*c*d**3*log(tan(e + f*x)**2 + 1)/(2*c**2*d**3*
f + 2*d**5*f) + 8*a**3*b*d**4*f*x/(2*c**2*d**3*f + 2*d**5*f) + 12*a**2*b**2*c**2*d**2*log(c/d + tan(e + f*x))/
(2*c**2*d**3*f + 2*d**5*f) - 12*a**2*b**2*c*d**3*f*x/(2*c**2*d**3*f + 2*d**5*f) + 6*a**2*b**2*d**4*log(tan(e +
f*x)**2 + 1)/(2*c**2*d**3*f + 2*d**5*f) - 8*a*b**3*c**3*d*log(c/d + tan(e + f*x))/(2*c**2*d**3*f + 2*d**5*f)
+ 8*a*b**3*c**2*d**2*tan(e + f*x)/(2*c**2*d**3*f + 2*d**5*f) - 4*a*b**3*c*d**3*log(tan(e + f*x)**2 + 1)/(2*c**
2*d**3*f + 2*d**5*f) - 8*a*b**3*d**4*f*x/(2*c**2*d**3*f + 2*d**5*f) + 8*a*b**3*d**4*tan(e + f*x)/(2*c**2*d**3*
f + 2*d**5*f) + 2*b**4*c**4*log(c/d + tan(e + f*x))/(2*c**2*d**3*f + 2*d**5*f) - 2*b**4*c**3*d*tan(e + f*x)/(2
*c**2*d**3*f + 2*d**5*f) + b**4*c**2*d**2*tan(e + f*x)**2/(2*c**2*d**3*f + 2*d**5*f) + 2*b**4*c*d**3*f*x/(2*c*
*2*d**3*f + 2*d**5*f) - 2*b**4*c*d**3*tan(e + f*x)/(2*c**2*d**3*f + 2*d**5*f) - b**4*d**4*log(tan(e + f*x)**2
+ 1)/(2*c**2*d**3*f + 2*d**5*f) + b**4*d**4*tan(e + f*x)**2/(2*c**2*d**3*f + 2*d**5*f), True))

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Giac [A]
time = 0.99, size = 238, normalized size = 1.25 \begin {gather*} \frac {\frac {2 \, {\left (a^{4} c - 6 \, a^{2} b^{2} c + b^{4} c + 4 \, a^{3} b d - 4 \, a b^{3} d\right )} {\left (f x + e\right )}}{c^{2} + d^{2}} + \frac {{\left (4 \, a^{3} b c - 4 \, a b^{3} c - a^{4} d + 6 \, a^{2} b^{2} d - b^{4} d\right )} \log \left (\tan \left (f x + e\right )^{2} + 1\right )}{c^{2} + d^{2}} + \frac {2 \, {\left (b^{4} c^{4} - 4 \, a b^{3} c^{3} d + 6 \, a^{2} b^{2} c^{2} d^{2} - 4 \, a^{3} b c d^{3} + a^{4} d^{4}\right )} \log \left ({\left | d \tan \left (f x + e\right ) + c \right |}\right )}{c^{2} d^{3} + d^{5}} + \frac {b^{4} d \tan \left (f x + e\right )^{2} - 2 \, b^{4} c \tan \left (f x + e\right ) + 8 \, a b^{3} d \tan \left (f x + e\right )}{d^{2}}}{2 \, f} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*tan(f*x+e))^4/(c+d*tan(f*x+e)),x, algorithm="giac")

[Out]

1/2*(2*(a^4*c - 6*a^2*b^2*c + b^4*c + 4*a^3*b*d - 4*a*b^3*d)*(f*x + e)/(c^2 + d^2) + (4*a^3*b*c - 4*a*b^3*c -
a^4*d + 6*a^2*b^2*d - b^4*d)*log(tan(f*x + e)^2 + 1)/(c^2 + d^2) + 2*(b^4*c^4 - 4*a*b^3*c^3*d + 6*a^2*b^2*c^2*
d^2 - 4*a^3*b*c*d^3 + a^4*d^4)*log(abs(d*tan(f*x + e) + c))/(c^2*d^3 + d^5) + (b^4*d*tan(f*x + e)^2 - 2*b^4*c*
tan(f*x + e) + 8*a*b^3*d*tan(f*x + e))/d^2)/f

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Mupad [B]
time = 5.78, size = 235, normalized size = 1.24 \begin {gather*} \frac {\mathrm {tan}\left (e+f\,x\right )\,\left (\frac {4\,a\,b^3}{d}-\frac {b^4\,c}{d^2}\right )}{f}-\frac {\ln \left (\mathrm {tan}\left (e+f\,x\right )+1{}\mathrm {i}\right )\,\left (a^4-a^3\,b\,4{}\mathrm {i}-6\,a^2\,b^2+a\,b^3\,4{}\mathrm {i}+b^4\right )}{2\,f\,\left (d+c\,1{}\mathrm {i}\right )}+\frac {b^4\,{\mathrm {tan}\left (e+f\,x\right )}^2}{2\,d\,f}-\frac {\ln \left (\mathrm {tan}\left (e+f\,x\right )-\mathrm {i}\right )\,\left (a^4\,1{}\mathrm {i}-4\,a^3\,b-a^2\,b^2\,6{}\mathrm {i}+4\,a\,b^3+b^4\,1{}\mathrm {i}\right )}{2\,f\,\left (c+d\,1{}\mathrm {i}\right )}+\frac {\ln \left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )\,\left (a^4\,d^4-4\,a^3\,b\,c\,d^3+6\,a^2\,b^2\,c^2\,d^2-4\,a\,b^3\,c^3\,d+b^4\,c^4\right )}{f\,\left (c^2\,d^3+d^5\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*tan(e + f*x))^4/(c + d*tan(e + f*x)),x)

[Out]

(tan(e + f*x)*((4*a*b^3)/d - (b^4*c)/d^2))/f - (log(tan(e + f*x) + 1i)*(a*b^3*4i - a^3*b*4i + a^4 + b^4 - 6*a^
2*b^2))/(2*f*(c*1i + d)) + (b^4*tan(e + f*x)^2)/(2*d*f) - (log(tan(e + f*x) - 1i)*(4*a*b^3 - 4*a^3*b + a^4*1i
+ b^4*1i - a^2*b^2*6i))/(2*f*(c + d*1i)) + (log(c + d*tan(e + f*x))*(a^4*d^4 + b^4*c^4 + 6*a^2*b^2*c^2*d^2 - 4
*a*b^3*c^3*d - 4*a^3*b*c*d^3))/(f*(d^5 + c^2*d^3))

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